Chemistry, 08.10.2019 19:00 williamrobinson93
Determine the rate law for the overall reaction (where the overall rate constant is represented as? consider the following mechanism
step 1: 2a > b+c slow
step 2: b+c > e fast
overall: 2a > e
determine the rate law for the overall reaction (where the overall rate constant is represented as k
rate=
explain how you got the answer and show steps
Answers: 3
Chemistry, 22.06.2019 06:00
Oxidation-reduction reactions (often called "redox" for short) are reactions that involve the transfer of electrons from one species to another. oxidation states, or oxidation numbers, allow chemists to keep track of these electron transfers. in general, one element will lose electrons (oxidation), with the result that it will increase in oxidation number, and another element will gain electrons (reduction), thereby decreasing in oxidation number. the species that is oxidized is called the reducing agent or reductant. the species that is reduced is called the oxidizing agent or oxidant. to sum up: oxidation = increase in oxidation state = loss of electrons = reducing agent reduction = decrease in oxidation state = gain of electrons = oxidizing agent part a which element is oxidized in this reaction? fe2o3+3co→2fe+3co2 enter the elemental symbol. view available hint(s) is oxidized part b which element is reduced in this reaction? 2hcl+2kmno4+3h2c2o4→6co2+2mno2+2kcl+4h2o enter the elemental symbol. view available hint(s) is reduced
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Chemistry, 23.06.2019 06:40
How many joules of heat are required to raise thetemperature of 750 g of water from 11.0 °c to 19.0 °c?
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Chemistry, 23.06.2019 07:30
Can you guys answer these questions i need it before 1: 00pm
Answers: 3
Chemistry, 23.06.2019 11:30
Place the following substances in order of ph from lowest ph to highest. a. neutral compounds, bases, acids b. acids, neutral compounds, bases c. bases, acids, neutral compounds d. bases, neutral compounds, acids
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Determine the rate law for the overall reaction (where the overall rate constant is represented as?...
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