10.0 ml of a 0.100 mol l–1 solution of a metal ion m2+ is mixed with 10.0 ml of a 0.100 mol l–1 solution of a substance l. the following equilibrium is established:
m2+(aq) + 2l(aq) picture ml22+(aq)
at equilibrium the concentration of l is found to be 0.0100 mol l–1. what is the equilibrium concentration of ml22+, in mol l–1?
someone me
Answers: 1
at equilibrium is 0.045 M.![[M^{2+}]_{initial}=0.100M](/tpl/images/0204/7051/8debc.png)
![[L]_{initial}=0.100M](/tpl/images/0204/7051/9e7cd.png)
![[L]_{eqllm}=0.0100M](/tpl/images/0204/7051/18682.png)
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10.0 ml of a 0.100 mol l–1 solution of a metal ion m2+ is mixed with 10.0 ml of a 0.100 mol l–1 solu...
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