Chemistry, 16.09.2019 15:50 conyabrew82

Propane camping stoves produce heat by the combustion of gaseous propane (c3h8). balance the skeletal equation for the combustion of propane.
c3h8(g)+o2(g)→co2(g)+h2o(g)

Answers: 1

Show answers

Answers

Answer from: P05182010

Explanation:

The given reaction is as follows.

$C_{3}H_{8}(g) + O_{2} \rightarrow CO_{2}(g) + H_{2}O(g)$

A balanced reaction is defined as the reaction which contains equal number of atoms on both reactant and product side.

Number of atoms on reactant side are as follows.

C = 13

H = 8

O = 2

Number of atoms on product side are as follows.

C = 1

O = 3

H = 2

Therefore, to balance this equation we multiply oxygen by 5 on reactant side. Also, we multiply $CO_{2}$ by 3 and $H_{2}O$ by 4 on product side by 2. Hence, the complete balanced chemical equation will be as follows.

$C_{3}H_{8}(g) + 5O_{2} \rightarrow 3CO_{2}(g) + 4H_{2}O(g)$

Answer from: Quest

here we have to get the change of moles on decrease the volume of the reaction in gas phase.

the per the given options it will decrease by (d) 11-50%

we know, on decreasing the volume of the gas phase reaction the reaction moves to the product side.

the reaction: so₂cl₂ (g) = so₂ (g) + cl₂ (g) total

the moles at equilibrium: 1 - α α α = 1+α

concentrations: 1 - α α α = 1 + α

(concentration = moles/volume, as volume is 1 l)

(where α is the degree of dissociation)

now the dissociation constant in terms of concentration is :

$k_{c}$ = $\frac{[so2cl2] x [cl2]}{[so2cl2]}$

or, $\frac{\alpha ^{2} }{(1-\alpha)v }$

or, $k_{c}$ = $\frac{\alpha ^{2} }{(1-\alpha) }$ (at v = 1l)

the reaction: so₂cl₂ (g) = so₂ (g) + cl₂ (g) total

the moles at equilibrium: 1 - α α α = 1+α

concentrations: (1 - α)/0.5 α/0.5 α/0.5 = (1 + α)/0.5

thus, the dissociation constant in terms of concentration is :

$\frac{[so2cl2] x [cl2]}{[so2cl2]}$

or, $\frac{\alpha ^{2} }{(1-\alpha)0.5 }$

$\frac{\alpha ^{2} }{(1-\alpha) }$ = $\frac{\alpha ^{2} }{(1-\alpha) 0.5}$

so, the change of 1 : 1/0.5

or, 1: 2

thus it will decrease by 50%.

or, as per the given options it will decrease by 11-50%

Answer from: Quest

D. most models represent a real world object in a simpler way

Another question on Chemistry

Chemistry, 21.06.2019 23:00

When determining the shape of a molecule, it is important to draw a lewis dot structure first in order to see the total number a. electrons within the moleculeb. bonding and unshared pairs around central atomc. unshared pair within the molecule( i really need it )

Answers: 1

Answer

Chemistry, 22.06.2019 12:30

The missing component to the table to the right or indicated with orange letters complete the table by filling in the corresponding numbers or symbols

Answers: 3

Answer

Chemistry, 22.06.2019 23:10

Amines are good nucleophiles, even though they are neutral molecules. how would the rate of an sn2 reaction between an amine and an alkyl halide be affected if the polarity of the solvent is increased? amines are good nucleophiles, even though they are neutral molecules. how would the rate of an reaction between an amine and an alkyl halide be affected if the polarity of the solvent is increased? because both reactants in the rate-limiting step are neutral, the reaction will be faster if the polarity of the solvent is increased. because both reactants in the rate-limiting step are neutral, the reaction will be slower if the polarity of the solvent is increased. because both reactants in the rate-limiting step are neutral, the reaction will occur at the same rate if the polarity of the solvent is increased. request answer

Answers: 3

Answer

Chemistry, 23.06.2019 00:00

#7 how does the structure of amino acids allow them to form a polypeptide? each amino acid has an amino group and a carboxyl group. each amino acid has a hydrogen atom and a carboxyl group. each amino acid has a carboxyl group and an r group. each amino acid has an r group and a hydrogen atom.

Answers: 1

Answer

You know the right answer?

Propane camping stoves produce heat by the combustion of gaseous propane (c3h8). balance the skeleta...

Questions