Match each number to how it would appear in scientific notation.
a. 8,330
8.33 × 10-3
b. 83.3
8.33 × 101
c. 0.00833
8.33 × 103
d. 0.0833
8.33 × 10-2
e. 83,330
8.33 × 104

8,330-->8.33 × 10^3

83.3-->8.33 × 10^1

0.00833-->8.33 × 10^-3

0.0833-->8.33 × 10^-2

83,330-->8.33 × 104

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2