Mercury can be obtained by reacting mercury(i) sulfide with calcium oxide. how many grams of calcium oxide are needed to produce 55.0 g of hg? note: 4 hg2s + 4 cao -> 8 hg + 3 cas + 1 caso4

First, 55 g of Hg is 3.65 moles because one mole of Hg has a molar mass of 200.59

Then, the mole ratio of Hg to CaO is 8:4 or 2:1. SO we divide 3.65 by 2 to get 1.82 moles of CaO

This is the same as 102.06 grams because one mole of CaO has a molar mass of 56.0774

Hope this helps!

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