When zn(oh)2(s) was added to 1.00 l of a basic solution, 1.09×10−2 mol of the solid dissolved. what is the concentration of oh− in the final solution? \

0.0218 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

where,

n= moles of solute

= volume of solution in Liters

According to stoichiometry:

1 mole of gives = 2 moles of

Thus gives =

Thus concentration of in the final solution will be 0.0218 M

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.