If 7.65 grams of iron (iii) oxide react with 6.85 grams of carbon monoxide to produce 5.10 g of pure iron, what are the theoretical yield and percent yield of this reaction? be sure to show the work that you did to solve this problem. unbalanced equation: fe2o3 + co yields fe + co2

Fe2O3 + 3 CO = 2 Fe + 3 CO2

mass of Fe = 7.65 g or 7.65 / 55.84 moles of Fe = 0.137 moles of Fe
3 * 0.137 moles of CO or 0.411 moles of CO
CO in the reaction = 6.85 / 28 = moles = 0.245 moles

moles (Fe produced )by these moles of CO = 3* 0.245 moles = 0.734 moles of Fe
theoretical mass produced (Fe) = 0.734 * 55.84 g = 41.00 g

5.10 g and a % yield of 5.10 /41.0 = 12.4 %