What is the oxidation number of mn in kmno4

Since O almost always has a charge of -2, the oxygen atoms have an overall charge of -8 (-2*4)

Since K has a charge of +1, that brings the overall charge to -7 (-8+1)

Then, in order for the overall charge to be 0, Mn would have to have a change of +7 (-7+7=0)

Hope this helps

KMnO₄ has an overall neutral charge, so that means that the total oxidation numbers should sum up to 0.

Oxygen will almost always have an oxidation number of -2, and K, because it is a group 1A metal, has an oxidation number of +1

There are 4 oxygens so the total oxidation number is 4*-2 = -8
And K has an oxidation number of +1

We are trying to find out the oxidation number of Mn. Remember since our compound is neutral, the sum of the oxidation numbers should be 0. So if we call the oxidation number of Mn as X, we then know that

X + (-8) + 1 = 0
X = -1 + 8
X = 7

Therefore, Mn has an oxidation number of 7.