Chemistry, 21.09.2019 02:40 korrinevbrulz2222

The rate law for a hypothetical reaction is rate=k[a][b]. if the concentration of a and b are both 0.020 miles per liter and k = 1.3x10-1m-1s-1, what is the reaction rate

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What you got here looks to be a plug-and-chug question
Note that mol/L = M

you know that

rate= k[a][b]

rate=?
k=1.3*10^-1 1/Ms
a=0.020 M
b=0.020 M

rate= (1.3*10^-1)(0.020)(0.020)= -->the units cancel out to give you M/s

rate= 0.000052 M/s

Answer from: janetexcoelho

Rate = 1.3×10⁻¹×0.02×0.02 = 5.2×10⁻⁵ mole-L⁻¹-s⁻¹

Answer from: Quest

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

Answer from: Quest

Answer: abeexplanation:

1. the question asks the most appropriate, which seems to rule out "all of the above." your choice appears to be the correct one.

2. the protocol described is good for identifying correlation, but not cause and effect. for cause/effect, you need to devise a protocol that will assign the treatment (or not) to groups that have essentially the same "demographics" with respect to all the other variables. your choice regarding control group seems appropriate. random assignment of treatment (choice d) may be appropriate also. (i think you can argue that b and d are just different descriptions of the same method.)

3. d will randomize the birds, but may not guarantee there are 10 in each group. e will do both, so seems the better choice.

comment on question 2

based on the problem statement, it seems clear that confident, attentive drivers are more likely to use daytime running lights. so, the protocol might need to be devised in such a way that the lights would be turned on or off without the driver's knowledge. (an attentive driver will figure it out.) assigning a confident, attentive driver to a group required to drive without running lights might mess with his/her confidence and attentiveness. you don't want your experiment to do that. (nor do you want the experiment to subject a driver to greater risk of accident as a consequence of driving without running lights.) experiments involving human safety are always problematic.

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The rate law for a hypothetical reaction is rate=k[a][b]. if the concentration of a and b are both 0...

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