How would you change the distance between two charged particles to increase the electric force between them by a factor of 16?
a. reduce the distance by a factor of 4.
b. increase the distance by a factor of 16.
c. increase the distance by a factor of 4.
d. reduce the distance by a factor of 16.

A. Reduce the distance by a factor of 4.

Explanation:

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

14 days is the half-life of phosphorus-32