In the balanced redox reaction 2 al(s) + 6 hcl(aq) → 2 alcl3(aq) + 3 h2(g) 80.0 ml of 2.0 m hcl would (theoretically) react with how many grams of al(s)? assume that the reaction is quantitative.
a. 1.44 g
b. 4.32 g
c. 1,440 g
d. 2,030 g
e. none of the above

The chemical reaction is written as:

 2 Al(s) + 6 HCl(aq) → 2 AlCl3(aq) + 3 H2(g)

We use the volume and the concentration of the acid to determine the number of moles HCl used. Then, we use relation from the reaction to determine the moles Al used. Finally, we convert it to grams by the molar mass.

(2.0 mol HCl / L) (.080 L) ( 2 mol Al / 6 mol HCl ) ( 26.98 g / mol ) = 1.44 g Al is used.

Answer(false);

Use the universal gas law formula: pv = nrt now, the key word in this problem is stp, so at stp, temperature will always be 0 degrees celsius and pressure will always be 1.0 atm or 760 torr. given something is at stp, we already know the two variables pressure and temperature. the other thing we can find with the given information is moles. to find moles, just divide grams by molar mass of the element. 16.0g / 2(16.00)g/mol = 0.5 moles plug the values in to the equation pv = nrt (1.0 atm)( x ) = (0.5 )(0+273=273k) the r value is just a constant for when we use atm, liters, moles and kelvin. i'm assuming you want your answer in liters, but if you dont just move the decimal 3 to the right in your final answer. so when plugging these numbers in to your calculator and trying to find x, you get 11.20665 liters using significant figures the answer is 11.2 liters