Abase is added to water. what happens when the position of equilibrium lies to the left?
a. the base is completely dissociating into products.
b. the base is partially dissociating into products.
c. the base is not dissociating into any ions.
d. the base is present in very small amounts.

B. The base is partially dissociating into products

Explanation:

If the reaction reaches equilibrium, it is reversible, so at the same time the reactants are producing the products, the products are producing the reactants. In equilibrium, the velocity of these reactions are the same, and the concentration remains constant.

So, let's suppose a base C(OH), in water its decomposition is:

C(OH) ⇄ C⁺ + OH⁻

If something disturbs the equilibrium, the reaction shift to the side that minimizes the disturb. So, if the position of equilibrium lies to the left, more reactant is formed, so fewer ions are formed, then the base is only partially dissociating into products.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o