Suppose 53.0 ml of 0.320 m koh is mixed with 28.0 ml of 0.250 m hno3. what is the concentration of oh- ions after the reaction goes to completion? express your answer in mol/l

Given:

Volume of KOH = 53.0 mL
Concentration of KOH = 0.320 M
Volume of HNO3 = 28.0 mL
Concentration of HNO3 = 0.250 M

Balanced Equation:

KOH + HNO3 ===> KNO3 + H2O

0.320   0.250        0              0

H2O ===> H+   +   OH-

Solve for the concentration of OH-

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And a) oxygen i believe