The following two experiments are carried out with anhydrous potassium chloride and
observations x and y are made at the end of each experiment.
concentrated sulfuric acid is added to the potassium chloride and the fumes produced are bubbled into aqueous potassium iodide solution - observation x.
the potassium chloride is dissolved in aqueous ammonia and this is then added to aqueous silver nitrate - observation y.
what are the observations x and y?

Observation X: The aqueous potassium iodide solution becomes yellow in color

Observation Y: A clear, colorless solution is observed.

Explanation:

Experiment 1

When Concentrated sulfuric acid is added to potassium chloride, hydrogen chloride gas is produced:

H₂SO₄ + 2KCl ⇒ 2HCl (g) + K₂SO₄

When the HCl gas is bubbled into aqueous potassium iodide, a redox reaction takes place at room temperature when energy is provided in the form of light:

4H⁺ + 4I⁻ + O₂ ⇒ 2I₂ + 2H₂O

The iodine causes the solution to become yellow in color (or darker yellow/brown at high concentrations of iodine).

Experiment 2:

When potassium chloride in aqueous ammonia is added to aqueous silver nitrate, the following net reaction occurs:

Ag⁺ + 2NH₃ ⇒ [Ag(NH₃)₂]⁺

The silver reacts with ammonia rather than chloride as ammonia is a better ligand in this case. The ammonia complex is soluble in water.

Thus, a clear, colorless solution will be observed.

it's all four options.

if the temperature drops and becomes cool

then the atmosphere can be freezing as the water vapor in the air is at maximum (100%) and can be severely cold

also can be snowing lightly as the moisture in the air will start to solidify

and btw this is not chemistry but