What concentration of so32– is in equilibrium with ag2so3(s and 3.40 × 10-3 m ag ? the ksp of ag2so3 can be found here?

To determine the concentration of the sulfate ion in equilibrium, we can use the ICE table.

        Ag2SO3 = 2Ag+ + SO3^2-
I            -               0           0
C          -             2x^2       x

E          -      3.40 × 10-3  x

 2x^2 = 3.40×10-3  
        x = 0.0412 M  = [SO3^2-]

Hope this answers the question. Have a nice day

Ithink it’s 3 as the answer.

Rn in the right answer