Which of the following changes would increase the rate of a reaction between vinegar and sodium hydroxide? (2 points) question 21 options: 1) heating up the vinegar 2) diluting the vinegar 3) cooling the sodium hydroxide 4) decreasing the volume of the container save

The correct answer is Option 1.

Explanation:

Rate of reaction can be increased by the following factors:

1. Concentration of the reactants: Greater the concentration of the reactants, faster is the reaction. Conversely, as the concentration of the reactants decrease, the rate of reaction also decreases.

2. Temperature: The rate of the reaction increases with increase in temperature.

3. Surface area of the reactants: For the reaction involving a solid reactant, the smaller is the particle size that is the greater is the surface area, faster will be the reaction.

From the given options, Temperature is playing the role in increasing the rate of the reaction.

Heating of vinegar will lead to the increase in the rate of the reaction because temperature is also increasing.

Hence, the correct answer is Option 1.

a. hope i'm right

explanation:

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.