Calculate the percent ionization of ha in a 0.10 m solution. express your answer as a percent using two significant figures.

The percent ionization of HA is 0.26 %

Explanation:

We are given:

Molarity of solution = 0.10 M

Let us assume that of the given acid is

The chemical equation for the ionization of HA follows:

Initial:            0.1

At eqllm:      (0.1-x)   x    x

The expression of for above equation follows:

We are given:

Putting values in above equation, we get:

Neglecting the negative value of 'x'.

To calculate the percent ionization, we use the equation:

Putting values in above equation, we get:

Hence, the percent ionization of HA is 0.26 %

the answer for sodium is 0.186

the answer for rubidium is 0.251

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