The melting of ice is represented by the following equation. h2o (s) ⇒ h2o (l) what would be the best argument against writing this in the form a chemical equation like this? a) there are no new products formed in this process. b) chemical reactions involve only one state of matter. c) it requires energy to melt ice and turn it into water. d) there are no coefficients in front of the product or reactants.

Option (C) is the correct answer.

Explanation:

In the given reaction it is shown that there occurs a change in state of water molecule from solid to liquid state.

When ice melts then basically heat is absorbed by it due to which its molecules gain kinetic energy. As a result, the atoms of water start to move from their initial position.

Hence, they collide rapidly with each other leading to change in state of ice from solid to liquid.

Therefore, we can conclude that it requires energy to melt ice and turn it into water would be the best argument against writing this in the form a chemical equation like this.

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole