A0.133 mol sample of gas in a 525 ml container has a pressure of 312 torr. the temperature of the gas is °
c.

The temperature of the gas is -253.25°C

Explanation:

To calculate the temperature of the gas, we use the equation given by ideal gas which follows:

where,

P = pressure of the gas = 312 torr

V = Volume of the gas = 525 mL = 0.525 L  (Conversion factor: 1 L = 1000 mL)

T = Temperature of the gas

R = Gas constant =

n = number of moles of gas = 0.133 mole

Putting values in above equation, we get:

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

Hence, the temperature of the gas is -253.25°C

your parents i think this could be it

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.