What volume does 8.5 g nh₃ occupy at stp?
a. 2.81 l
b. 5.61 l
c. 11.21 l
d. 22.41 l
e. 44.81 l

First, convert grams to moles by dividing 8.5 by the molar mass of NH₃ (N=14,H=1)

14+1+1+1=17

8.5/17=.5 moles NH₃

Multiply .5 by the conversion factor of moles to L (22.4)

.5*22.4=11.2 L NH₃

11.2 is just 11.21 rounded down, so your answer is C) 11.21 L

Explanation:

b

explanation:

mitosis

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.