Given a 1.50 liters of solution that contains 62.5 grams of magnesium oxide. what is the molarity of that solution

Molarity (M) is moles over liters (moles/liters), so convert grams to moles using the molar mass of MgO and then divide the moles of MgO over the liters given.

So it would look like this:

Step 1: 62.5 g MgO x (1 mole MgO/40.31 g MgO) = 1.55 mol MgO

Step 2: 1.55 mol MgO/1.5 L = 1.03 M MgO

You need to divided twenty four by a dozen them by the temperature it is getting cook by

The problem here is that according to aufbau principle before 3d orbital 4s subshell comes.after filling 3p orbital with electrons you have 4 electrons left, you place two in 4s with opposite spin and the other two in 3d in any of its two orbitals of total five orbitals with the same spin.