Asolution of h2so4(aq) with a molal concentration of 3.58 m has a density of 1.200 g/ml. what is the molar concentration of this solution?

Best A molality of 2.55 indicates 2.55 mol of solute per 1 kg of solvent. Assume exactly 1 kg of water, and thus 2.55 mol of H2SO4.

The molar mass of H2SO4 is 2(1.0079 g/mol) (32.066 g/mol) 4(15.999 g/mol)=98.0778 g/mol.

2.55 mol H2SO4 x (98.0778g / 1 mol) = 2.50 x 10^2 g H2SO4

The mass of the water is 1 kg = 1000 g. the total mass of solution is

(2.50 x 10^2 g H2SO4) + (1000 g H2O) = 1.250 x 10^3 g solution

Use the mass and density of the solution to find the volume

1.250 x 10^3 g solution x (1 mL / 1.151g ) x (1 L / 1000mL) = 1.086 L solution

Finally, molarity is the number of moles of solute per liter of solution

(2.55 mol H2SO4 / 1.086 L solution ) = 2.35 M
Source(s):
Sapling Learning.com (the website we do our chemistry homework and that was the response given to me. good luck. hope you got it on time...

What record? the question is incomplete

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