What is the mass in grams of 9.06 x 10^24 molecules of methanol (ch3oh)?

Explanation:

As we know that according to Avogadro, 1 mole of an atom contains atoms.

So, number of atoms given in the methanol are . Hence, calculate the number of moles present as follows.

   No. of moles =

                         = 15.04 mol    

As molar mass of methanol is 32.04 g/mol. Hence, the mass of given methanol is as follows.

          No. of moles =

               15.04 mol =

             mass = 481.28 g

Thus, we can conclude that mass of molecules of methanol () is 481.28 g.

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.