This is the equation for the dissociation of ammonia gas at 293 k. h = 145 kj and s = 195 j/k.

2nh3(g) n2(g) + 3h2(g)

which correctly states the g for this dissociation and whether the process is spontaneous or nonspontaneous? use g = h – ts.

We are given the equation for the dissociation of ammonia gas at 293 K. 

2NH3 (g) ==> N2(g) + 3H2(g)

and H = 145 kJ; S = 195 J/K

To determine the Gibb's Free Energy for this reaction, use the formula:

G = H - TS
substitute the given values:
G = 145x10^3 J - 293K * 195 J/K
G = 87865 Joules

The dissociation of ammonia gas has a positive Gibb's Free Energy, thus, the reaction is not spontaneous. Spontaneous reactions have Gibb's Free Energy which is less than zero or a negative number. 

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer