Name the following compound ch2=ch - ch3

prop-1-ene

Explanation:

The IUPAC nomenclature of alkenes are given as follows:

Select the longest possible carbon chain.  The numbering is done from the end from where the double bond gets the lower number.

For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.

If two of more similar alkyl groups are present, then the words 'di', 'tri' 'tetra' and so on are used to specify the number of times these alkyl groups appear in the chain. A suffix '-ene' is added at the end of the name after the position of the double bond.

Hence, the name for given hydrocarbon will be prop-1-ene.