The buoyant force acting on a submerged object equals the weight of the fluid displaced by the object. what is the weight of the water displaced by a block of iron with the dimensions of 3.00 cm x 3.00 cm x 3.00 cm? the iron has a mass of 213 g. remember that water has a density of 1.00 g/cm3. hint: determine the volume of the displaced water. then determine the mass using your knowledge of the density of water. finally, convert the mass to weight using weight = mg, where mass is in kilograms and gravity, g = 9.80 m/s2.

27.0 g
2.76 g
265 n
0.265 n

 The buoyant force acting on a submerged object equals the weight of the fluid displaced by the object. What is the weight of the water displaced by a block of iron with the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. It has a mass of 213 g. Remember that water has a density of 1.00 g/cm3. 

To determine the weight of the displaced water, we need to know the volume of the block. Since the entire block is submerged, the volume of displaced water = volume of block!! 

Volume of block = 3 * 3 * 3 = 27 cubic cm 
Now we need to determine the weight of 27 cc of water. 
Weight = mass in kg * 9.8 

Density = mass / volume 
1 g/cc = mass / 27 
Mass = 27 g 

Weight = mass in kg * 9.8 
Mass in kg = 0.027 kg 
Weight of block = 0.027 * 9.8 = 0.2646 N 

The buoyant force acting on a submerged object equals the weight of the fluid displaced by the object. 

Buoyant force = 0.2646 N 
a is incorrect, because force is weight, not mass 
d is correct, 

The answer is 1.82 j/g°c