Will up-vote

a force of 2,500 pounds drags a truck 30 feet in 1/2 minute.

how much work is accomplished?

how much power was required?

work = 75,000 ft-lbs, power = 32, 5000 ft-lbs/sec
work = 7,500 ft-lbs, power = 250 ft-lbs/sec
work= 75,000 ft-lbs, power = 2,500 ft-lbs/sec

In order to calculate the work done on a body, we find the product of the force applied on the body and the displacement produced in the direction of the force. Mathematically:
Work = Force * displacement
Work = 2,500 * 30
Work = 75,000 ft-lbs

Power is the rate of work done, this is:
Power = Work / time
Power = 75,000 / 30
Power = 2,500 ft-lbs/sec

Work= 75,000 ft-lbs, Power = 2,500 ft-lbs/sec

Perimeter? wheres the answers