Me.

a 60 l cylinder is filled with argon gas to a pressure of 10130.0 kpa at 200°c. how many moles of argon gas does the cylinder contain? (given: r = 8.314 l∙kpa/k∙mol)

To simplify, we need to assume that the gas is an ideal gas so we can use the equation PV=nRT where P is pressure, V is volume, n is the number of moles, R is the universal gas constant and T is the temperature. We can calculate as follows:
PV = nRT
n = PV / RT
n = 10130(60) / 8.314 (200+273.15)
n = 154.51 mol argon gas

Where is the graph ?