Someone fr ! what is the freezing point in celsius of a 1.56 m aqueous solution of cacl2? (report amount to 3 decimal points)

-8.705 °C (amount to three decimal points/ significant figures)

Explanation:

1. This is a water solution so, you will need to know the freezing and boiling point of water.

Freezing point of water in Kf (°C/m) = 1.86 °C/m

Boiling point of water in Kb (°C/m) = 0.512 °C/m

2. There are 3 number of particles in CaCl2

3. Multiple the number of particles and the 1.56 m to the freezing and boiling point of water.

4. (Freezing Point) Kfm (1.86)*(1.56)*(3) = 8.7048

5. (Boiling Point) Kbm (0.512)*(1.56)*(3) = 2.39616

6. Subtract the Freezing point of water in °C (Celsius) which is 0.0 °C from the answer 8.7048 ( 0 - 8.7048 = -8.7048 °C

7. Add the Boiling point of water in °C (Celsius) which is 100.0 °C from the answer 2.39616 ( 100 + 2.39616 = 102.39616)

8. The question is asking for the Freezing point of 1.56 m which is what we now know to be -8.7048 °C

9. The answer in 3 decimal points will round up to -8.705 °C

10. The reason is because 0 does not count as a significant figure so you need the “5” to make this answer have 3 significant figures which are the numbers 8, 7 and 5 which makes it round up to the 3 decimal points.

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.