The specific heat of a substance is 2.01 j/g·°
c. if given 10.3 grams of the substance and if 542 joules of heat is absorbed, what is the change in temperature of the substance?

The change in temperature is 26.4 C

Explanation:

Given:

Mass of the substance, m = 10.3 g

Specific heat of the substance, c = 2.01 J/g C

Heat absorbed, q = 542 J

To determine:

The change in temperature, ΔT

Explanation:

The amount of heat (q) absorbed (or evolved) by  a substance of mass (m) in order to bring a temperature change of (ΔT) is given as:

In this case:

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.