In an experiment, 12.0dm3 of oxygen, measured under room conditions, is used to burn completely 0.10mol of propan-1-ol. what is the final volume of gas, measured under room conditions? a 7.20dm3 b 8.40dm3 c 16.8dm3 d 18.00dm3 ans is b. pls explain how

The correct answer is option D.

Explanation:

At room conditions ,temperature is taken as T =293.15 k

At room conditions, pressure is taken as P = 1 atm

Given the volume of oxygen gas = = 12.0 L

Using Ideal gas equation:

n = 0.4992033 moles of oxygen gas.

Initial number of moles of oxygen gas = 0.4992 mol

According to reaction, 2 moles of propanol reacts with 9 moles of oxygen.

Then 0.10 moles of propanol will react with:

Final moles of oxygen gas left after combustion reaction = n'

n'= 0.4992 mol - 0.45 mol = 0.0492 mol

So, the final volume of the oxygen gas measured will be given as:V'

V' = 1.18 L

Volume of the

According to reaction, 2 moles of propanol gives  with 6 moles of .

Then 0.10 moles of propanol will give :

Volume of the

According to reaction, 2 moles of propanol gives  with 8 moles of .

Then 0.10 moles of propanol will give :

Total volume of the gas measured =

thats how its supposed to be