What is the mass of ca(oh)2 in 110. ml of 1.244 m ca(oh)2 solution

V= 110mL = 110cm³ = 0,11dm³
C = 1,244 mol/L = 1,244 mol/dm³

C = n/V
n = 1,244×0,11
n = 0,13684 moles

mCa(OH)₂ = 74 g/mol

1 mole Ca(OH)₂  74g
0,13684 X
X = 74×0,13684
X = 10,12616g

:)

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na

Is a logical series of steps