Each astronaut produces 8.8 x 10^2 grams of co2 per day that must be removed from the air on the shuttle if typical shuttle mission is 9 days and the shuttle can carry 3.5 x 10^4 grams lioh what is the maximum number of people the shuttle can safely carry for one mission?

M₀(CO₂)=8.8*10² g
m(LiOH)=3.5*10⁴ g
x=9 d

2LiOH + CO₂ = Li₂CO₃ + H₂O

m(CO₂)=M(CO₂)m(LiOH)/2M(LiOH)

N=m(CO₂)/xm₀(CO₂)=M(CO₂)m(LiOH)/{2M(LiOH)xm₀(CO₂)}

N=44.01*3.5*10⁴/{2*23.95*9*8.8*10²}=4

The maximum number of people is 4.

It is also possible the reaction:
Li₂CO₃ + CO₂ + H₂O = 2LiHCO₃

You would do 1500/4 and the answer is 375