The ka of an acid is 1.3 mc020-1.jpg 10–7. based on the ka and its relationship with kw, what is the value of kb?

 The Ka of the acid is 1.3 * 10^ -7.

Ka is the constant of dissociation of the acid.

Kb is the constant of dissociation of the conjugated base

The relationship between Ka and Kb is:

Ka * Kb = Kw = 1 * 10 ^-`14

=> Kb = Kw / Ka

=> Kb = [1 * 10 ^ -14 ] / [1.3 * 10 ^ -7] = 7.69 * 10 ^-8 = 7.7 * 10 ^ -8

7.7 * 10^-8