How much heat is required to raise the temperature of a 2.0 kg of water (specific heat = 1.0 cal/g°c) from 5.0°c to 100.0°c?

The heat required to raise the temperature of 2 kg of water from 5°C to 100°C is 190000 cal (190 Kcal).

Explanation:

To solve this problem you have to use the formula that relates the heat (q) with mass (m), specific heat (s) and variation of the temperature (ΔT) for the substance. You have to express mass in units of grs, so 2 kg =2000 grs.

⇒ q = m·s·ΔT⇒ q = (2000 grs)·(1.0 cal/g°C)·(100°C - 5°C)

⇒q= 190000 cal = 190 Kcal.

The heat required to raise the temperature of 2 kg of water from 5°C to 100°C is 190000 cal (190 Kcal).

um i think it might be a car?

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally