Accurately calculate the concentration of the diluted solution starting with the concentration of the stock fe(no3)3 solution (0.2 m).

Ans: 25 mM

For example, suppose we take the following concentrations:

Diluted Fe =1 ml 

1 M KSCN = 5 ml 

0.1 M HN = 2  ml 
----------------------------------------
Then, total volume = 8 ml 

Now, 
 final concentration of  diluted Fe = 

given stock solution is 0.2 M

Thus, concentration of diluted solution = 

Cause its being chemically applied?