An element has three naturally occurring isotopes. use the information below to calculate the weighted average atomic mass of the element, showing both the setup and the final answer for the calculation. isotope atomic mass percent abundance i 39.96 u 99.59% ii 37.96 u 0.065% iii 35.97 u 0.336%

In order to calculate an average, we should sum all numbers and divide them by quantity.

Let’s work with qualifications first. Let’s say you got a 10 in 1 exam, then an 8 in 2 exams and a 4 in 2 exams. Your average will be:

= (10*1+8*2+4*2) / 5 = 6.8

If 6 is the minimum, you will pass.

There is another way to calculate this average: applying distributive property.

= 10*1/5+8*2/5+4*2/5 = 6.8

Remember you can convert the fractions into equivalent fractions: 1/5 = 20/100; 2/5 = 40/100

= 10*20/100+8*20/100+4*20/100 = 6.8

We actually don’t have the number of atoms of each mass… we have the percentage instead! So we need to learn this last method for atoms.

Let’s go back to our atoms problem:

Average mass = 39,94 u

your answer is c) plasma

~*"auba14"*~

може ли да зареждате повече информация, моля