Ascientist needs to collect a 0.050 mole sample of helium, but needs to know how large his helium container should be. what volume is needed to store the sample of helium gas at 202.6kpa and 400k? a. 657 milliliters b. 760 milliliters c. 820 milliliters d. 1,025 milliliters

We can use the ideal gas equation:

PV = nRT

P = 202.6kPa = 202600 Pa (You have to multiply by 1000)

n = 0.050 mole

R = 0.082 atm*l/(K*mol)

T = 400K

We will have to convert from Pa to atm or viceversa.

101325 Pa1 atm

202600 Pax = 2.00 atm

2atm*V = 0.050 mole*0.082 atm*l/(K*mol)* 400K

V = 0.050 mole*0.082 atm*l/(K*mol)* 400K/2atm = 0.82 liters = 820 mililiters

im not exactly sure but i think its b!

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.