How many grams of magnesium metal will react completely with 4.8 liters of 5.0 m hcl? show all of the work needed to solve this problem. mg (s) + 2hcl (aq) mgcl2 (aq) + h2 (g)

291.72 grams of magnesium metal will react completely with 4.8 liters of 5.0 M HCl.

Explanation:

Concentration of 4,8 L  HCl solution = 5.0 M

Moles of HCl in solution = n

n = 24 moles

According to reaction , 2 moles of HCl reacts with 1 mole of magnesium metal.

Then 24 moles of HCl will react with :

of magnesium

Mass of 12 moles of magnesium = 12 mol × 24.31 g/mol=291.72g

291.72 grams of magnesium metal will react completely with 4.8 liters of 5.0 M HCl.

what is the volume occupied by 40 grams of argon gas (ar) at standard conditions? what volume, in liters, is occupied by 1.5 x 1023 

the answer is a and have a great day