How many milliliters of sodium metal, with a density of 0.97 g/ml, would be needed to produce 53.2 grams of hydrogen gas in the single-replacement reaction below? show all steps of your calculation as well as the final answer.

na + h2o → naoh + h2

my
1. balance the equation: 2na + 2h2o --> 2naoh + h2
2. take the known amount of 54.2 g h2 and convert it into moles, multiply by the mole ratio (number of moles from the balanced equation, unknown substance over the given substance) and convert it back into grams:
53.2 g h2 x 1 mol h2/ 2 g h2 x 2 moles na/ 1 mol h2 x 22.98 g/ 1 mol na = 1222 g na
1 gram = 1 ml,
so 1222 ml of na