If 65.5 moles of an ideal gas is at 9.15 atm at 50.30 °c, what is the volume of the gas?

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To calculate for the volume, we need a relation to relate the number of moles (n), pressure (P), and temperature (T) with volume (V). For simplification, we assume the gas is an ideal gas. So, we use PV=nRT.

PV = nRT  where R is the universal gas constant
V = nRT / P
V = 65.5 ( 0.08205 ) (273.15 + 50.30) / 9.15 
V = 189.98 L

Hi; /c

Fine out you self hx