Using the standard enthalpies of formation found in the textbook, determine the enthalpy change for the combustion of ethanol c2h5oh as given below. c2h5oh (l) + 3 o2(g) → 2 co2(g) + 3 h2o(g)

-1367.5 kJ

Explanation:

The balanced chemical reaction is,

The expression for enthalpy change is,

where,

n = number of moles

Now put all the given values in this expression, we get

Therefore, the enthalpy change for this reaction is, -1367.5 kJ

the answer is 1 i believe

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.