In the reaction hcl (aq) + naoh (aq) → nacl (aq) + h2o (l), if 45.0 milliliters of a 2.0 m hcl react in an excess of naoh, how many grams of h2o will be produced?

1) Chemical equation

HCl (aq) + NaOH (aq) --> NaCl (aq) + H2O (l)

2) Molar ratios

1 mol HCl : 1 mol NaOh : 1 mol NaCl : 1 mol H2O

3) Number of moles of HCl:

M = n / V => n = M * V = 2.0M * 0.045 l = 0.09 mol

4) Use the adequate proportion:

1mol HCl / 1 mol H2O = 0.09 mol HCl / x => x = 0.09 mol H2O

5) Use the molar mass of H2O to convert moles to grams

=> 0.09 mol * 18.0 g/mol = 1.62 g

1.62 g