Suppose you perform an experiment at 21.5 oc and 1.00 atm and generate helium gas in the laboratory. what do you expect the molar volume of the helium to be?

The molar volume is the volume of 1 mol and it is calculated as:

molar Volume = Voumen / number of moles = V / n

Now use the formula pV = nRT, and molar volume = V / n

=> molar volumen = V / n = RT / p

=> V / n = 0.0821 atm*l / K*mol * (21.5 + 273.15)K / 1.00 atm

=> V/n = 24.19 l / mol

24.19 l / mol

The answer is 65.3312