How many moles of nacl are required to prepare 0.80 l of 6.4 m nacl? 0.13 mol nacl 5.1 mol nacl 7.2 mol nacl 8.0 mol nacl?

5.12 moles of NaCl are required to prepare 0.80 L of 6.4 M NaCl.

Explanation:

Molarity (M) is a concentration measure that indicates the number of moles of solute that are dissolved in a given volume.

The Molarity is then determined by:

Molarity is expressed in units.

6.4 M NaCl indicates that 1 liter of solution there are 6.4 moles of NaCl.

You can apply a rule of three as follows: if in 1 liter of solution there are 6.4 moles of NaCl, in 0.8 L how many moles are there?

moles=5.12

5.12 moles of NaCl are required to prepare 0.80 L of 6.4 M NaCl.

answer; i believe the correct answer is (solid gold);

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.