Find the ph of a 0.250 m solution of nac2h3o2. (the ka value of hc2h3o2 is 1.80×10−5).

When NaC2H3O2 is in solution, it would act as a base since it ionizes into sodium ions and acetate ions, the acetate ions would interact with water with the following reaction:

C2H3O2- + H2O <---> C2H3O2H + OH-  

So, from the reaction, hydroxide ions are formed giving it basic properties. We calculate as follows:

[NaC2H3O2] = [Na+] = [C2H3O2-] = 0.250 m

By the ICE table:
            [C2H3O2-]         C2H3O2H      OH-
I              0.250                     0                0
C                -x                      +x               +x

E            0.250 - x                x                 x         

 1.80×10^−5 = x^2 / (0.250 - x)

Solving for x, we have 

x = 0.002112

pOH = -log 0.002112

pOH = 2.68

pH = 14 - 2.68 = 11.32

Therefore, the pH of the solution is about 11.32.

alienation, transformation, consumption, and the relativity of truth.

you can choose any one of these, they are all important themes.

these themes reflect the distinct sensibilities of both the modernist and postmodern aesthetic movements. (from google, you should paraphrase)

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