You have prepared a saturated solution of x at 20∘c using 37.0 g of water. how much more solute can be dissolved if the temperature is increased to 30∘c?

To the prepared solution at   the extra mass of x to be added to the solution at   will be 4.44 g.

The complete question has given:

Solubility of x/100 g water at = 11

Solubility of x/100 g water at = 23

Now, since the saturated solution at  will use 37 g of water. The mass of x in the saturated solution will be :

Mass of x =  

Mass of x at = g

Mass of x at  = 4.07 g.

The mass of solute at will be = g.

The mass of solute at  = 8.51 g.

The extra mass of x to be added to the solution will be = 8.51 - 4.07 g.

The extra mass of x to be added to the solution will be 4.44 g.

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