How many atoms of carbon are contained in 47.6 g of al2(co3)3? the molar mass of al2(co3)3 is 233.99 g/mol?

The molar mass of Al₂(CO₃)₃is 233.99 g/mol

It means 233.99 grams of Al₂(CO₃)₃ are in one mole

And moles in 47.6 g = 47.6/233.99 = 0.203 moles

Now we know that we have 0.203 moles of Al₂(CO₃)₃

In one mole of Al₂(CO₃)₃, we have 3 moles of carbon

To find the number of moles of carbon in a 0.203 moles of Al₂(CO₃)₃, we must multiply this by the 3 moles of carbon 

0.203 x 3 = 0.609 moles of carbon 

Within one mole of carbon, we have 6.022 x 10²³ atoms. So, to find the amount of atoms within 0.609 moles of carbon, we must multiply the 0.609 moles by 6.022 x 10²³ atoms. 

So, the number of carbon atoms present in 47.6g of Al₂(CO₃)₃ = 0.609 x 6.022 x 10²³ = 3.667 x 10²³ atoms.

the answer to your question is c