What is the molarity of a solution that is made by dissolving 3.68 g of sucrose (c12h22o11) in sufficient water to form 275.0 ml of solution?

The molarity of the solution is 0.03 M.

Molarity of a solution can be defined as the moles of solute present in a liter of the solution.

In the given question,

weight of sucrose = 3.68 g

Volume of solution = 275 ml

We know, the molecular weight of sucrose = 342 grams/mol

Molarity = 0.03 M.

The molarity of the solution is 0.03 M.

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