Question 25 a chemist determined by measurements that 0.020 moles of mercury participated in a chemical reaction. calculate the mass of mercury that participated in the chemical reaction. round your answer to 2 significant digits.

To solve this question, we first need to know the mass of one mole of mercury. This can be done by checking the periodic table.

From the periodic table, we can see that:
molar mass of mercury = 200.59 grams/mole.

From the measurements, the chemist found that the participated amount of mercury is 0.02 moles.

We can simply determine the mass of 0.02 moles by doing cross multiplication as follows:
mass of 0.02 moles = (0.02 x 200.59) / 1 = 4.0118 grams

Rounding the answer to 2 significant digits, we get:
mass of 0.02 moles = 4.01 grams

The mass of the mercury that participated in the chemical reaction is 4.01 g

Mole is simply defined as the unit of amount of a substance. It can be expressed mathematically as:

Mole = mass / molar mass

With the above formula, we can obtain the mass of mercury that participated in the reaction as follow:

Mole of Mercury = 0.020 moles

Molar mass of mercy = 200.59 g/mol

Mass of mercury =?

Mole = mass / molar mass

0.02 = mass / 200.59

Cross multiply

Mass = 0.02 × 200.59

Mass of mercury = 4.01 g

Therefore, the mass of mercury that participated in the chemical reaction is 4.01 g

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